Born This Way

Description:

Input:

The first line contains five integers $$$n$$$, $$$m$$$, $$$t_a$$$, $$$t_b$$$ and $$$k$$$ ($$$1 \le n, m \le 2 \cdot 10^5$$$, $$$1 \le k \le n + m$$$, $$$1 \le t_a, t_b \le 10^9$$$) — the number of flights from A to B, the number of flights from B to C, the flight time from A to B, the flight time from B to C and the number of flights you can cancel, respectively.

The second line contains $$$n$$$ distinct integers in increasing order $$$a_1$$$, $$$a_2$$$, $$$a_3$$$, ..., $$$a_n$$$ ($$$1 \le a_1 < a_2 < \ldots < a_n \le 10^9$$$) — the times the flights from A to B depart.

The third line contains $$$m$$$ distinct integers in increasing order $$$b_1$$$, $$$b_2$$$, $$$b_3$$$, ..., $$$b_m$$$ ($$$1 \le b_1 < b_2 < \ldots < b_m \le 10^9$$$) — the times the flights from B to C depart.

Output:

If you can cancel $$$k$$$ or less flights in such a way that it is not possible to reach C at all, print $$$-1$$$.

Otherwise print the earliest time Arkady can arrive at C if you cancel $$$k$$$ flights in such a way that maximizes this time.

Sample Input:

4 5 1 1 2
1 3 5 7
1 2 3 9 10

Sample Output:

11

Sample Input:

2 2 4 4 2
1 10
10 20

Sample Output:

-1

Sample Input:

4 3 2 3 1
1 999999998 999999999 1000000000
3 4 1000000000

Sample Output:

1000000003

Note:

Consider the first example. The flights from A to B depart at time moments $$$1$$$, $$$3$$$, $$$5$$$, and $$$7$$$ and arrive at B at time moments $$$2$$$, $$$4$$$, $$$6$$$, $$$8$$$, respectively. The flights from B to C depart at time moments $$$1$$$, $$$2$$$, $$$3$$$, $$$9$$$, and $$$10$$$ and arrive at C at time moments $$$2$$$, $$$3$$$, $$$4$$$, $$$10$$$, $$$11$$$, respectively. You can cancel at most two flights. The optimal solution is to cancel the first flight from A to B and the fourth flight from B to C. This way Arkady has to take the second flight from A to B, arrive at B at time moment $$$4$$$, and take the last flight from B to C arriving at C at time moment $$$11$$$.

In the second example you can simply cancel all flights from A to B and you're done.

In the third example you can cancel only one flight, and the optimal solution is to cancel the first flight from A to B. Note that there is still just enough time to catch the last flight from B to C.