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C+=

2000ms 524288K

Description:

Leo has developed a new programming language C+=. In C+=, integer variables can only be changed with a "+=" operation that adds the right-hand side value to the left-hand side variable. For example, performing "a += b" when a = $$$2$$$, b = $$$3$$$ changes the value of a to $$$5$$$ (the value of b does not change).

In a prototype program Leo has two integer variables a and b, initialized with some positive values. He can perform any number of operations "a += b" or "b += a". Leo wants to test handling large integers, so he wants to make the value of either a or b strictly greater than a given value $$$n$$$. What is the smallest number of operations he has to perform?

Input:

The first line contains a single integer $$$T$$$ ($$$1 \leq T \leq 100$$$) — the number of test cases.

Each of the following $$$T$$$ lines describes a single test case, and contains three integers $$$a, b, n$$$ ($$$1 \leq a, b \leq n \leq 10^9$$$) — initial values of a and b, and the value one of the variables has to exceed, respectively.

Output:

For each test case print a single integer — the smallest number of operations needed. Separate answers with line breaks.

Sample Input:

2
1 2 3
5 4 100

Sample Output:

2
7

Note:

In the first case we cannot make a variable exceed $$$3$$$ in one operation. One way of achieving this in two operations is to perform "b += a" twice.

Informação

Codeforces

Provedor Codeforces

Código CF1368A

Tags

brute forcegreedyimplementationmath

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Taxa de BOUA's 0%

Datas 09/05/2023 10:03:43

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