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New Game Plus!

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Description:

Wabbit is playing a game with $$$n$$$ bosses numbered from $$$1$$$ to $$$n$$$. The bosses can be fought in any order. Each boss needs to be defeated exactly once. There is a parameter called boss bonus which is initially $$$0$$$.

When the $$$i$$$-th boss is defeated, the current boss bonus is added to Wabbit's score, and then the value of the boss bonus increases by the point increment $$$c_i$$$. Note that $$$c_i$$$ can be negative, which means that other bosses now give fewer points.

However, Wabbit has found a glitch in the game. At any point in time, he can reset the playthrough and start a New Game Plus playthrough. This will set the current boss bonus to $$$0$$$, while all defeated bosses remain defeated. The current score is also saved and does not reset to zero after this operation. This glitch can be used at most $$$k$$$ times. He can reset after defeating any number of bosses (including before or after defeating all of them), and he also can reset the game several times in a row without defeating any boss.

Help Wabbit determine the maximum score he can obtain if he has to defeat all $$$n$$$ bosses.

Input:

The first line of input contains two spaced integers $$$n$$$ and $$$k$$$ ($$$1 \leq n \leq 5 \cdot 10^5$$$, $$$0 \leq k \leq 5 \cdot 10^5$$$), representing the number of bosses and the number of resets allowed.

The next line of input contains $$$n$$$ spaced integers $$$c_1,c_2,\ldots,c_n$$$ ($$$-10^6 \leq c_i \leq 10^6$$$), the point increments of the $$$n$$$ bosses.

Output:

Output a single integer, the maximum score Wabbit can obtain by defeating all $$$n$$$ bosses (this value may be negative).

Sample Input:

3 0
1 1 1

Sample Output:

3

Sample Input:

5 1
-1 -2 -3 -4 5

Sample Output:

11

Sample Input:

13 2
3 1 4 1 5 -9 -2 -6 -5 -3 -5 -8 -9

Sample Output:

71

Note:

In the first test case, no resets are allowed. An optimal sequence of fights would be

  • Fight the first boss $$$(+0)$$$. Boss bonus becomes equal to $$$1$$$.
  • Fight the second boss $$$(+1)$$$. Boss bonus becomes equal to $$$2$$$.
  • Fight the third boss $$$(+2)$$$. Boss bonus becomes equal to $$$3$$$.

Thus the answer for the first test case is $$$0+1+2=3$$$.

In the second test case, it can be shown that one possible optimal sequence of fights is

  • Fight the fifth boss $$$(+0)$$$. Boss bonus becomes equal to $$$5$$$.
  • Fight the first boss $$$(+5)$$$. Boss bonus becomes equal to $$$4$$$.
  • Fight the second boss $$$(+4)$$$. Boss bonus becomes equal to $$$2$$$.
  • Fight the third boss $$$(+2)$$$. Boss bonus becomes equal to $$$-1$$$.
  • Reset. Boss bonus becomes equal to $$$0$$$.
  • Fight the fourth boss $$$(+0)$$$. Boss bonus becomes equal to $$$-4$$$.

Hence the answer for the second test case is $$$0+5+4+2+0=11$$$.

Informação

Codeforces

Provedor Codeforces

Código CF1415E

Tags

constructive algorithmsgreedymath

Submetido 0

BOUA! 0

Taxa de BOUA's 0%

Datas 09/05/2023 10:06:40

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