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Catching Cheaters

1000ms 262144K

Description:

You are given two strings $$$A$$$ and $$$B$$$ representing essays of two students who are suspected cheaters. For any two strings $$$C$$$, $$$D$$$ we define their similarity score $$$S(C,D)$$$ as $$$4\cdot LCS(C,D) - |C| - |D|$$$, where $$$LCS(C,D)$$$ denotes the length of the Longest Common Subsequence of strings $$$C$$$ and $$$D$$$.

You believe that only some part of the essays could have been copied, therefore you're interested in their substrings.

Calculate the maximal similarity score over all pairs of substrings. More formally, output maximal $$$S(C, D)$$$ over all pairs $$$(C, D)$$$, where $$$C$$$ is some substring of $$$A$$$, and $$$D$$$ is some substring of $$$B$$$.

If $$$X$$$ is a string, $$$|X|$$$ denotes its length.

A string $$$a$$$ is a substring of a string $$$b$$$ if $$$a$$$ can be obtained from $$$b$$$ by deletion of several (possibly, zero or all) characters from the beginning and several (possibly, zero or all) characters from the end.

A string $$$a$$$ is a subsequence of a string $$$b$$$ if $$$a$$$ can be obtained from $$$b$$$ by deletion of several (possibly, zero or all) characters.

Pay attention to the difference between the substring and subsequence, as they both appear in the problem statement.

You may wish to read the Wikipedia page about the Longest Common Subsequence problem.

Input:

The first line contains two positive integers $$$n$$$ and $$$m$$$ ($$$1 \leq n, m \leq 5000$$$) — lengths of the two strings $$$A$$$ and $$$B$$$.

The second line contains a string consisting of $$$n$$$ lowercase Latin letters — string $$$A$$$.

The third line contains a string consisting of $$$m$$$ lowercase Latin letters — string $$$B$$$.

Output:

Output maximal $$$S(C, D)$$$ over all pairs $$$(C, D)$$$, where $$$C$$$ is some substring of $$$A$$$, and $$$D$$$ is some substring of $$$B$$$.

Sample Input:

4 5
abba
babab

Sample Output:

5

Sample Input:

8 10
bbbbabab
bbbabaaaaa

Sample Output:

12

Sample Input:

7 7
uiibwws
qhtkxcn

Sample Output:

0

Note:

For the first case:

abb from the first string and abab from the second string have LCS equal to abb.

The result is $$$S(abb, abab) = (4 \cdot |abb|$$$) - $$$|abb|$$$ - $$$|abab|$$$ = $$$4 \cdot 3 - 3 - 4 = 5$$$.

Informação

Codeforces

Provedor Codeforces

Código CF1446B

Tags

dpstrings

Submetido 0

BOUA! 0

Taxa de BOUA's 0%

Datas 09/05/2023 10:08:30

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