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Binary String Partition

2000ms 262144K

Description:

Let's call a string $$$t$$$ consisting of characters 0 and/or 1 beautiful, if either the number of occurrences of character 0 in this string does not exceed $$$k$$$, or the number of occurrences of characters 1 in this string does not exceed $$$k$$$ (or both). For example, if $$$k = 3$$$, the strings 101010, 111, 0, 00000, 1111111000 are beautiful, and the strings 1111110000, 01010101 are not beautiful.

You are given a string $$$s$$$. You have to divide it into the minimum possible number of beautiful strings, i. e., find a sequence of strings $$$t_1, t_2, \dots, t_m$$$ such that every $$$t_i$$$ is beautiful, $$$t_1 + t_2 + \dots + t_m = s$$$ (where $$$+$$$ is the concatenation operator), and $$$m$$$ is minimum possible.

For every $$$k$$$ from $$$1$$$ to $$$|s|$$$, find the minimum possible number of strings such that $$$s$$$ can be divided into them (i. e. the minimum possible $$$m$$$ in the partition).

Input:

The only line contains one string $$$s$$$ ($$$1 \le |s| \le 2 \cdot 10^5$$$). Each character of $$$s$$$ is either 0 or 1.

Output:

Print $$$|s|$$$ integers. The $$$i$$$-th integer should be equal to the minimum number of strings in the partition of $$$s$$$, when $$$k = i$$$.

Sample Input:

00100010

Sample Output:

2 1 1 1 1 1 1 1

Sample Input:

1001011100

Sample Output:

3 2 2 2 1 1 1 1 1 1

Informação

Codeforces

Provedor Codeforces

Código CF1533F

Tags

*specialbinary searchgreedy

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Datas 09/05/2023 10:14:47

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