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Getting Zero

2000ms 262144K

Description:

Suppose you have an integer $$$v$$$. In one operation, you can:

  • either set $$$v = (v + 1) \bmod 32768$$$
  • or set $$$v = (2 \cdot v) \bmod 32768$$$.

You are given $$$n$$$ integers $$$a_1, a_2, \dots, a_n$$$. What is the minimum number of operations you need to make each $$$a_i$$$ equal to $$$0$$$?

Input:

The first line contains the single integer $$$n$$$ ($$$1 \le n \le 32768$$$) — the number of integers.

The second line contains $$$n$$$ integers $$$a_1, a_2, \dots, a_n$$$ ($$$0 \le a_i < 32768$$$).

Output:

Print $$$n$$$ integers. The $$$i$$$-th integer should be equal to the minimum number of operations required to make $$$a_i$$$ equal to $$$0$$$.

Sample Input:

4
19 32764 10240 49

Sample Output:

14 4 4 15 

Note:

Let's consider each $$$a_i$$$:

  • $$$a_1 = 19$$$. You can, firstly, increase it by one to get $$$20$$$ and then multiply it by two $$$13$$$ times. You'll get $$$0$$$ in $$$1 + 13 = 14$$$ steps.
  • $$$a_2 = 32764$$$. You can increase it by one $$$4$$$ times: $$$32764 \rightarrow 32765 \rightarrow 32766 \rightarrow 32767 \rightarrow 0$$$.
  • $$$a_3 = 10240$$$. You can multiply it by two $$$4$$$ times: $$$10240 \rightarrow 20480 \rightarrow 8192 \rightarrow 16384 \rightarrow 0$$$.
  • $$$a_4 = 49$$$. You can multiply it by two $$$15$$$ times.

Informação

Codeforces

Provedor Codeforces

Código CF1661B

Tags

bitmasksbrute forcedfs and similardpgraphsgreedyshortest paths

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Datas 09/05/2023 10:23:40

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