Preparando MOJI

AND Sorting

1000ms 262144K

Description:

You are given a permutation $$$p$$$ of integers from $$$0$$$ to $$$n-1$$$ (each of them occurs exactly once). Initially, the permutation is not sorted (that is, $$$p_i>p_{i+1}$$$ for at least one $$$1 \le i \le n - 1$$$).

The permutation is called $$$X$$$-sortable for some non-negative integer $$$X$$$ if it is possible to sort the permutation by performing the operation below some finite number of times:

  • Choose two indices $$$i$$$ and $$$j$$$ $$$(1 \le i \lt j \le n)$$$ such that $$$p_i \& p_j = X$$$.
  • Swap $$$p_i$$$ and $$$p_j$$$.

Here $$$\&$$$ denotes the bitwise AND operation.

Find the maximum value of $$$X$$$ such that $$$p$$$ is $$$X$$$-sortable. It can be shown that there always exists some value of $$$X$$$ such that $$$p$$$ is $$$X$$$-sortable.

Input:

The input consists of multiple test cases. The first line contains a single integer $$$t$$$ $$$(1 \le t \le 10^4)$$$  — the number of test cases. Description of test cases follows.

The first line of each test case contains a single integer $$$n$$$ $$$(2 \le n \le 2 \cdot 10^5)$$$  — the length of the permutation.

The second line of each test case contains $$$n$$$ integers $$$p_1, p_2, ..., p_n$$$ ($$$0 \le p_i \le n-1$$$, all $$$p_i$$$ are distinct)  — the elements of $$$p$$$. It is guaranteed that $$$p$$$ is not sorted.

It is guaranteed that the sum of $$$n$$$ over all cases does not exceed $$$2 \cdot 10^5$$$.

Output:

For each test case output a single integer — the maximum value of $$$X$$$ such that $$$p$$$ is $$$X$$$-sortable.

Sample Input:

4
4
0 1 3 2
2
1 0
7
0 1 2 3 5 6 4
5
0 3 2 1 4

Sample Output:

2
0
4
1

Note:

In the first test case, the only $$$X$$$ for which the permutation is $$$X$$$-sortable are $$$X = 0$$$ and $$$X = 2$$$, maximum of which is $$$2$$$.

Sorting using $$$X = 0$$$:

  • Swap $$$p_1$$$ and $$$p_4$$$, $$$p = [2, 1, 3, 0]$$$.
  • Swap $$$p_3$$$ and $$$p_4$$$, $$$p = [2, 1, 0, 3]$$$.
  • Swap $$$p_1$$$ and $$$p_3$$$, $$$p = [0, 1, 2, 3]$$$.

Sorting using $$$X = 2$$$:

  • Swap $$$p_3$$$ and $$$p_4$$$, $$$p = [0, 1, 2, 3]$$$.

In the second test case, we must swap $$$p_1$$$ and $$$p_2$$$ which is possible only with $$$X = 0$$$.

Informação

Codeforces

Provedor Codeforces

Código CF1682B

Tags

bitmasksconstructive algorithmssortings

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Datas 09/05/2023 10:28:25

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