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LCM Sum (hard version)

3000ms 524288K

Description:

We are sum for we are many
Some Number

This version of the problem differs from the previous one only in the constraint on $$$t$$$. You can make hacks only if both versions of the problem are solved.

You are given two positive integers $$$l$$$ and $$$r$$$.

Count the number of distinct triplets of integers $$$(i, j, k)$$$ such that $$$l \le i < j < k \le r$$$ and $$$\operatorname{lcm}(i,j,k) \ge i + j + k$$$.

Here $$$\operatorname{lcm}(i, j, k)$$$ denotes the least common multiple (LCM) of integers $$$i$$$, $$$j$$$, and $$$k$$$.

Input:

Each test contains multiple test cases. The first line contains the number of test cases $$$t$$$ ($$$\bf{1 \le t \le 10^5}$$$). Description of the test cases follows.

The only line for each test case contains two integers $$$l$$$ and $$$r$$$ ($$$1 \le l \le r \le 2 \cdot 10^5$$$, $$$l + 2 \le r$$$).

Output:

For each test case print one integer — the number of suitable triplets.

Sample Input:

5
1 4
3 5
8 86
68 86
6 86868

Sample Output:

3
1
78975
969
109229059713337

Note:

In the first test case, there are $$$3$$$ suitable triplets:

  • $$$(1,2,3)$$$,
  • $$$(1,3,4)$$$,
  • $$$(2,3,4)$$$.

In the second test case, there is $$$1$$$ suitable triplet:

  • $$$(3,4,5)$$$.

Informação

Codeforces

Provedor Codeforces

Código CF1712E2

Tags

brute forcedata structuresmathnumber theorytwo pointers

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Datas 09/05/2023 10:30:28

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