Preparando MOJI

Even Subarrays

2000ms 262144K

Description:

You are given an integer array $$$a_1, a_2, \dots, a_n$$$ ($$$1 \le a_i \le n$$$).

Find the number of subarrays of $$$a$$$ whose $$$\operatorname{XOR}$$$ has an even number of divisors. In other words, find all pairs of indices $$$(i, j)$$$ ($$$i \le j$$$) such that $$$a_i \oplus a_{i + 1} \oplus \dots \oplus a_j$$$ has an even number of divisors.

For example, numbers $$$2$$$, $$$3$$$, $$$5$$$ or $$$6$$$ have an even number of divisors, while $$$1$$$ and $$$4$$$ — odd. Consider that $$$0$$$ has an odd number of divisors in this task.

Here $$$\operatorname{XOR}$$$ (or $$$\oplus$$$) denotes the bitwise XOR operation.

Print the number of subarrays but multiplied by 2022... Okay, let's stop. Just print the actual answer.

Input:

Each test contains multiple test cases. The first line contains the number of test cases $$$t$$$ ($$$1 \leq t \leq 10^4$$$). Description of the test cases follows.

The first line of each test case contains a single integer $$$n$$$ ($$$2 \leq n \leq 2 \cdot 10^5$$$) — the length of the array $$$a$$$.

The second line contains $$$n$$$ integers $$$a_1, a_2, \dots, a_n$$$ ($$$1 \leq a_i \leq n$$$).

It is guaranteed that the sum of $$$n$$$ over all test cases does not exceed $$$2 \cdot 10^5$$$.

Output:

For each test case, print the number of subarrays, whose $$$\operatorname{XOR}$$$ has an even number of divisors.

Sample Input:

4
3
3 1 2
5
4 2 1 5 3
4
4 4 4 4
7
5 7 3 7 1 7 3

Sample Output:

4
11
0
20

Note:

In the first test case, there are $$$4$$$ subarrays whose $$$\operatorname{XOR}$$$ has an even number of divisors: $$$[3]$$$, $$$[3,1]$$$, $$$[1,2]$$$, $$$[2]$$$.

In the second test case, there are $$$11$$$ subarrays whose $$$\operatorname{XOR}$$$ has an even number of divisors: $$$[4,2]$$$, $$$[4,2,1]$$$, $$$[4,2,1,5]$$$, $$$[2]$$$, $$$[2,1]$$$, $$$[2,1,5]$$$, $$$[2,1,5,3]$$$, $$$[1,5,3]$$$, $$$[5]$$$, $$$[5,3]$$$, $$$[3]$$$.

In the third test case, there is no subarray whose $$$\operatorname{XOR}$$$ has an even number of divisors since $$$\operatorname{XOR}$$$ of any subarray is either $$$4$$$ or $$$0$$$.

Informação

Codeforces

Provedor Codeforces

Código CF1731C

Tags

bitmasksbrute forcehashingmathnumber theory

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Datas 09/05/2023 10:31:42

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