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Divide and Conquer

1000ms 262144K

Description:

An array $$$b$$$ is good if the sum of elements of $$$b$$$ is even.

You are given an array $$$a$$$ consisting of $$$n$$$ positive integers. In one operation, you can select an index $$$i$$$ and change $$$a_i := \lfloor \frac{a_i}{2} \rfloor$$$. $$$^\dagger$$$

Find the minimum number of operations (possibly $$$0$$$) needed to make $$$a$$$ good. It can be proven that it is always possible to make $$$a$$$ good.

$$$^\dagger$$$ $$$\lfloor x \rfloor$$$ denotes the floor function — the largest integer less than or equal to $$$x$$$. For example, $$$\lfloor 2.7 \rfloor = 2$$$, $$$\lfloor \pi \rfloor = 3$$$ and $$$\lfloor 5 \rfloor =5$$$.

Input:

Each test contains multiple test cases. The first line contains a single integer $$$t$$$ ($$$1 \leq t \leq 1000$$$) — the number of test cases. The description of the test cases follows.

The first line of each test case contains a single integer $$$n$$$ ($$$1 \leq n \leq 50$$$) — the length of the array $$$a$$$.

The second line of each test case contains $$$n$$$ space-separated integers $$$a_1,a_2,\ldots,a_n$$$ ($$$1 \leq a_i \leq 10^6$$$) — representing the array $$$a$$$.

Do note that the sum of $$$n$$$ over all test cases is not bounded.

Output:

For each test case, output the minimum number of operations needed to make $$$a$$$ good.

Sample Input:

4
4
1 1 1 1
2
7 4
3
1 2 4
1
15

Sample Output:

0
2
1
4

Note:

In the first test case, array $$$a$$$ is already good.

In the second test case, we can perform on index $$$2$$$ twice. After the first operation, array $$$a$$$ becomes $$$[7,2]$$$. After performing on index $$$2$$$ again, $$$a$$$ becomes $$$[7,1]$$$, which is good. It can be proved that it is not possible to make $$$a$$$ good in less number of operations.

In the third test case, $$$a$$$ becomes $$$[0,2,4]$$$ if we perform the operation on index $$$1$$$ once. As $$$[0,2,4]$$$ is good, answer is $$$1$$$.

In the fourth test case, we need to perform the operation on index $$$1$$$ four times. After all operations, $$$a$$$ becomes $$$[0]$$$. It can be proved that it is not possible to make $$$a$$$ good in less number of operations.

Informação

Codeforces

Provedor Codeforces

Código CF1762A

Tags

greedymathnumber theory

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Datas 09/05/2023 10:33:57

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