Preparando MOJI
There are $$$n$$$ departments in the mall, each of which has exactly two stores. For convenience, we number the departments with integers from $$$1$$$ to $$$n$$$. It is known that gifts in the first store of the $$$i$$$ department cost $$$a_i$$$ rubles, and in the second store of the $$$i$$$ department — $$$b_i$$$ rubles.
Entering the mall, Sasha will visit each of the $$$n$$$ departments of the mall, and in each department, he will enter exactly one store. When Sasha gets into the $$$i$$$-th department, he will perform exactly one of two actions:
Sasha is going to buy at least one gift for each friend. Moreover, he wants to pick up gifts in such a way that the price difference of the most expensive gifts bought for friends is as small as possible so that no one is offended.
More formally: let $$$m_1$$$ be the maximum price of a gift bought to the first friend, and $$$m_2$$$ be the maximum price of a gift bought to the second friend. Sasha wants to choose gifts in such a way as to minimize the value of $$$\lvert m_1 - m_2 \rvert$$$.
Each test contains multiple test cases. The first line contains the number of test cases $$$t$$$ ($$$1 \le t \le 1\,000$$$). The description of the test cases follows.
The first line of each test case contains a single integer $$$n$$$ ($$$2 \le n \le 500\,000$$$) — the number of departments in the mall.
Each of the following $$$n$$$ lines of each test case contains two integers $$$a_i$$$ and $$$b_i$$$ ($$$0 \le a_i, b_i \le 10^9$$$) — the prices of gifts in the first and second store of the $$$i$$$ department, respectively.
It is guaranteed that the sum of $$$n$$$ over all test cases does not exceed $$$500\,000$$$.
Print one integer — the minimum price difference of the most expensive gifts bought to friends.
221 22 151 52 73 34 102 5
0 1
In the first test case, Sasha has two possible options: buy a gift for the first friend in the first department, and the second friend — in the second department, or vice versa. In the first case, $$$m_1 = m_2 = 1$$$, and in the second case — $$$m_1 = m_2 = 2$$$. In both cases, the answer is $$$0$$$. In the second test case, you can buy gifts for the first friend in the $$$2$$$, $$$4$$$ and $$$5$$$ departments, and for the second friend — in the $$$1$$$ and $$$3$$$ departments.So $$$m_1 = \max(2, 4, 2) = 4$$$, $$$m_2 = \max(5, 3) = 5$$$. The answer is $$$\lvert 4 - 5 \rvert = 1$$$.