Preparando MOJI

XOR Counting

2000ms 262144K

Description:

Given two positive integers $$$n$$$ and $$$m$$$. Find the sum of all possible values of $$$a_1\bigoplus a_2\bigoplus\ldots\bigoplus a_m$$$, where $$$a_1,a_2,\ldots,a_m$$$ are non-negative integers such that $$$a_1+a_2+\ldots+a_m=n$$$.

Note that all possible values $$$a_1\bigoplus a_2\bigoplus\ldots\bigoplus a_m$$$ should be counted in the sum exactly once.

As the answer may be too large, output your answer modulo $$$998244353$$$.

Here, $$$\bigoplus$$$ denotes the bitwise XOR operation.

Input:

Each test consists of multiple test cases. The first line contains a single integer $$$t$$$ ($$$1 \le t \le 10^4$$$) — the number of test cases. The description of test cases follows.

The first and only line of each test case contains two integers $$$n$$$ and $$$m$$$ ($$$0\le n\le 10^{18}, 1\le m\le 10^5$$$) — the sum and the number of integers in the set, respectively.

Output:

For each test case, output the sum of all possible values of $$$a_1\bigoplus a_2\bigoplus\ldots\bigoplus a_m$$$ among all non-negative integers $$$a_1,a_2,\ldots,a_m$$$ with $$$a_1+a_2+\ldots+a_m=n$$$. As the answer may be too large, output your answer modulo $$$998244353$$$.

Sample Input:

7
69 1
5 2
0 10
420 69
12 26
73 34
1000000000000000000 10

Sample Output:

69
6
0
44310
42
1369
216734648

Note:

For the first test case, we must have $$$a_1=69$$$, so it's the only possible value of $$$a_1$$$, therefore our answer is $$$69$$$.

For the second test case, $$$(a_1,a_2)$$$ can be $$$(0,5), (1,4), (2,3), (3,2), (4,1)$$$ or $$$(5,0)$$$, in which $$$a_1\bigoplus a_2$$$ are $$$5,5,1,1,5,5$$$ respectively. So $$$a_1\bigoplus a_2$$$ can be $$$1$$$ or $$$5$$$, therefore our answer is $$$1+5=6$$$.

For the third test case, $$$a_1,a_2,\ldots,a_{10}$$$ must be all $$$0$$$, so $$$a_1\bigoplus a_2\bigoplus\ldots\bigoplus a_{10}=0$$$. Therefore our answer is $$$0$$$.

Informação

Codeforces

Provedor Codeforces

Código CF1815D

Tags

bitmaskscombinatoricsdpmath

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Datas 09/05/2023 10:38:35

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