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Number Challenge

3000ms 524288K

Description:

Let's denote d(n) as the number of divisors of a positive integer n. You are given three integers a, b and c. Your task is to calculate the following sum:

Find the sum modulo 1073741824 (230).

Input:

The first line contains three space-separated integers a, b and c (1 ≤ a, b, c ≤ 2000).

Output:

Print a single integer — the required sum modulo 1073741824 (230).

Sample Input:

2 2 2

Sample Output:

20

Sample Input:

4 4 4

Sample Output:

328

Sample Input:

10 10 10

Sample Output:

11536

Note:

For the first example.

  • d(1·1·1) = d(1) = 1;
  • d(1·1·2) = d(2) = 2;
  • d(1·2·1) = d(2) = 2;
  • d(1·2·2) = d(4) = 3;
  • d(2·1·1) = d(2) = 2;
  • d(2·1·2) = d(4) = 3;
  • d(2·2·1) = d(4) = 3;
  • d(2·2·2) = d(8) = 4.

So the result is 1 + 2 + 2 + 3 + 2 + 3 + 3 + 4 = 20.

Informação

Codeforces

Provedor Codeforces

Código CF235E

Tags

combinatoricsdpimplementationmathnumber theory

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Datas 09/05/2023 08:40:03

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