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Drawing Circles is Fun

3000ms 262144K

Description:

There are a set of points S on the plane. This set doesn't contain the origin O(0, 0), and for each two distinct points in the set A and B, the triangle OAB has strictly positive area.

Consider a set of pairs of points (P1, P2), (P3, P4), ..., (P2k - 1, P2k). We'll call the set good if and only if:

  • k ≥ 2.
  • All Pi are distinct, and each Pi is an element of S.
  • For any two pairs (P2i - 1, P2i) and (P2j - 1, P2j), the circumcircles of triangles OP2i - 1P2j - 1 and OP2iP2j have a single common point, and the circumcircle of triangles OP2i - 1P2j and OP2iP2j - 1 have a single common point.

Calculate the number of good sets of pairs modulo 1000000007 (109 + 7).

Input:

The first line contains a single integer n (1 ≤ n ≤ 1000) — the number of points in S. Each of the next n lines contains four integers ai, bi, ci, di (0 ≤ |ai|, |ci| ≤ 50; 1 ≤ bi, di ≤ 50; (ai, ci) ≠ (0, 0)). These integers represent a point .

No two points coincide.

Output:

Print a single integer — the answer to the problem modulo 1000000007 (109 + 7).

Sample Input:

10
-46 46 0 36
0 20 -24 48
-50 50 -49 49
-20 50 8 40
-15 30 14 28
4 10 -4 5
6 15 8 10
-20 50 -3 15
4 34 -16 34
16 34 2 17

Sample Output:

2

Sample Input:

10
30 30 -26 26
0 15 -36 36
-28 28 -34 34
10 10 0 4
-8 20 40 50
9 45 12 30
6 15 7 35
36 45 -8 20
-16 34 -4 34
4 34 8 17

Sample Output:

4

Sample Input:

10
0 20 38 38
-30 30 -13 13
-11 11 16 16
30 30 0 37
6 30 -4 10
6 15 12 15
-4 5 -10 25
-16 20 4 10
8 17 -2 17
16 34 2 17

Sample Output:

10

Informação

Codeforces

Provedor Codeforces

Código CF372E

Tags

combinatoricsgeometry

Submetido 0

BOUA! 0

Taxa de BOUA's 0%

Datas 09/05/2023 08:48:01

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