Fibonacci-ish II

5000ms

524288K

Description:

Yash is finally tired of computing the length of the longest Fibonacci-ish sequence. He now plays around with more complex things such as Fibonacci-ish potentials.

Fibonacci-ish potential of an array a_i is computed as follows:

Remove all elements j if there exists i < j such that a_i = a_j.
Sort the remaining elements in ascending order, i.e. a₁ < a₂ < ... < a_n.
Compute the potential as P(a) = a₁·F₁ + a₂·F₂ + ... + a_n·F_n, where F_i is the i-th Fibonacci number (see notes for clarification).

You are given an array a_i of length n and q ranges from l_j to r_j. For each range j you have to compute the Fibonacci-ish potential of the array b_i, composed using all elements of a_i from l_j to r_j inclusive. Find these potentials modulo m.

Input:

The first line of the input contains integers of n and m (1 ≤ n, m ≤ 30 000) — the length of the initial array and the modulo, respectively.

The next line contains n integers a_i (0 ≤ a_i ≤ 10⁹) — elements of the array.

Then follow the number of ranges q (1 ≤ q ≤ 30 000).

Last q lines contain pairs of indices l_i and r_i (1 ≤ l_i ≤ r_i ≤ n) — ranges to compute Fibonacci-ish potentials.

Output:

Print q lines, i-th of them must contain the Fibonacci-ish potential of the i-th range modulo m.

Sample Input:

Sample Output:

3
3

Note:

For the purpose of this problem define Fibonacci numbers as follows:

F₁ = F₂ = 1.
F_n = F_n - 1 + F_n - 2 for each n > 2.

In the first query, the subarray [1,2,1] can be formed using the minimal set {1,2}. Thus, the potential of this subarray is 1*1+2*1=3.

Informação

Provedor Codeforces

Código CF633H