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Palindrome Partition

3000ms 262144K

Description:

Given a string s, find the number of ways to split s to substrings such that if there are k substrings (p1, p2, p3, ..., pk) in partition, then pi = pk - i + 1 for all i (1 ≤ i ≤ k) and k is even.

Since the number of ways can be large, print it modulo 109 + 7.

Input:

The only line of input contains a string s (2 ≤ |s| ≤ 106) of even length consisting of lowercase Latin letters.

Output:

Print one integer, the number of ways of partitioning the string modulo 109 + 7.

Sample Input:

abcdcdab

Sample Output:

1

Sample Input:

abbababababbab

Sample Output:

3

Note:

In the first case, the only way to partition the string is ab|cd|cd|ab.

In the second case, the string can be partitioned as ab|b|ab|ab|ab|ab|b|ab or ab|b|abab|abab|b|ab or abbab|ab|ab|abbab.

Informação

Codeforces

Provedor Codeforces

Código CF932G

Tags

dpstring suffix structuresstrings

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Datas 09/05/2023 09:24:14

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