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Scissors

1000ms 262144K

Description:

Jenya has recently acquired quite a useful tool — k-scissors for cutting strings. They are generally used for cutting out two non-intersecting substrings of length k from an arbitrary string s (its length should be at least k in order to perform this operation) and concatenating them afterwards (preserving the initial order). For example, with the help of 2-scissors you can cut ab and de out of abcde and concatenate them into abde, but not ab and bc since they're intersecting.

It's a nice idea to test this tool before using it in practice. After looking through the papers, Jenya came up with two strings s and t. His question is whether it is possible to apply his scissors to string s such that the resulting concatenation contains t as a substring?

Input:

The first line contains three integers n, m, k (2 ≤ m ≤ 2·k ≤ n ≤ 5·105) — length of s, length of t and the aforementioned scissors' parameter correspondingly.

The next two lines feature s and t consisting of lowercase latin letters.

Output:

If there is no answer, print «No».

Otherwise print «Yes» and two integers L and R denoting the indexes where cutted substrings start (1-indexed). If there are several possible answers, output any.

Sample Input:

7 4 3
baabaab
aaaa

Sample Output:

Yes
1 5

Sample Input:

6 3 2
cbcbcb
bcc

Sample Output:

Yes
2 5

Sample Input:

7 5 3
aabbaaa
aaaaa

Sample Output:

No

Note:

In the first sample case you can cut out two substrings starting at 1 and 5. The resulting string baaaab contains aaaa as a substring.

In the second sample case the resulting string is bccb.

Informação

Codeforces

Provedor Codeforces

Código CF955D

Tags

brute forcestrings

Submetido 0

BOUA! 0

Taxa de BOUA's 0%

Datas 09/05/2023 09:32:57

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